Let {xn} be a sequence of random variables. p (a) if xn ~ 0, then for any p > 0 ixnip ~ o 1 + ixnip and p (b) if for some p > 0 (6.21) holds, then xn ~ 0. (c) suppose p > 0. show xn ~ 0 iff (6.22).

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

cosine

step-by-step explanation:

answer: i don't understand it

step-by-step explanation: sorry

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58