Amagazine currently has 8700 subscribers for its online web version. it is adding members at the rate of r(t) = 190e0.03t subscribers per month. if the proportion of members who remain subscribed t months from now is s(t) = e−0.06t, how many online subscribers will the magazine have three years from now? (round your answer to the nearest integer.)

Number of subscriber the magazine will have after 3 years from now approximately be 8767

Solution:

Given that magazine currently has 8700 subscribers for its online web version

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

true !

step-by-step explanation:

step-by-step explanation: 4 cause 2+2=4