Choose the point-slope form of the equation below that represents the line that passes through the point (6, −3) and has a slope of fraction 1 over 2 .

y + 3 = (1/2)(x -6)

Step-by-step explanation:

When we have the slope m of the line and a point (a,b) which the line passes through, the point-slope form is

y - b = m (x -a)

Since the slope is 1/2 and the line passes through (6, -3), the point-slope equation is

y -(-3) = (1/2)(x -6)

or

y + 3 = (1/2)(x -6)

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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you answer is a

step-by-step explanation: