Concrete blocks are produced in lots of 2000. each block has probability 0.85 of meeting a strength specification. the blocks are independent. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. what is the probability that, in a given lot, fewer than 1690 blocks meet the specification?

Step-by-step explanation:

Let us assume a normal distribution

The formula for normal distribution is

z = (x - u)/s

Where

u = mean = np

s = standard deviation = √npq

x = number of blocks that meet the specification

n = number of blocks sampled

From the information given,

p = 0.85 = probability that the block will meet the strength specification.

q = 1 - p = 1 - 0.85 = 0.15 = probability that the block will not meet the strength specification.

n = 2000

u = np = 2000 × 0.85 = 1700

s = √npq = √1700×0.15 = 15.97

We want to find the P(x lesser than 1690). It becomes

z = (1690 - 1700)/15.97

z = -10/15.9 = -0.63

Looking at the normal distribution table for the corresponding z score, it is 0.2644

Therefore

P(x lesser than 1690) = 0.2644

answer: no idea

step-by-step explanation: i just want points

answer: $34.31

step-by-step explanation:

$11.99 x 3 = $35.97

$35.97 - 10% = $32.37

$32.37 + 6% = $34.31