Of the 36 students in a certain class, 10 are in the chess club and 13 are in the bridge club. if 20 of the students are not in either club, how many of the students are in only one of the two clubs? a. 7b. 9c. 14d. 16e. 23

There are 9 students in only one of the two clubs.

Step-by-step explanation:

Since we have given that

Number of students = 36

Number of students are in chess club = 10

Number of students are in bridge club = 13

Number of students are not in either club = 20

So, Number of students in both the club is given by

Number of students only in chess = 10-7 =3

Number of students only in bridge = 13-7=6

Hence, there are 3+6=9 students in only one of the two clubs.

110698.56 square miles

step-by-step explanation:

multiply 3.8 by 102

387.6

multiply 2.8 by 102

285.6

multiply those two to get

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.