Find a model for simple harmonic motion if the position at t = 0 is 2, the

amplitude is 2 centimeters, and the period is 6 seconds.

o a. d= 6 sin(2t)

o b. d = 2 cos(6t)

o c. d= 2 sin(pi/3t)

o d. d= 2cos(pi/3t)

submit

Option D.

Step-by-step explanation:

Given information:

Amplitude = 2  centimeters

Period = 6 seconds

Position at t = 0 is 2.

In simple harmonic motion the displacement is defined as

          .... (1)

where, A is amplitude and f is frequency.

Substitute A=2 and in equation (1).

Therefore, the correct option is D.

1 1/5

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !