Asample of 100 receipts from a restaurant showed that 12 had errors. what is the 95% confidence interval for the proportion of all receipts that have error? note that z 0.025= 1.96 and t 0.025= 1.984 for 99 degrees of freedom?

0.03919

Step-by-step explanation:

You take 1.984+1.96=3.944

3.944-0.025=3.919

3.919 into the percentage =0.03919

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844