For $n \ge 0$, let $f_n$ denote the $n$th fibonacci number (that is, $f_0 = 0, f_1 = 1$, and $f_n = f_{n-1} + f_{n-2}$ for all $n \ge 2$). what is the greatest possible value of the greatest common divisor of two consecutive fibonacci numbers?

`1234567890-=/*-qwertyuiop[]asdfghjkl; '\\zxcvbnm,./+ /

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.