∘
, m∠v = (7x+16)^{\circ}(7x+16)
Mathematics, 28.11.2019 19:31 deadman7628
In δuvw, m∠u = (2x-17)^{\circ}(2x−17)
∘
, m∠v = (7x+16)^{\circ}(7x+16)
∘
, and m∠w = (4x-1)^{\circ}(4x−1)
∘
. find m∠u.
Answers: 1
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You know the right answer?
In δuvw, m∠u = (2x-17)^{\circ}(2x−17)
∘
, m∠v = (7x+16)^{\circ}(7x+16)
∘
, m∠v = (7x+16)^{\circ}(7x+16)
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