According to the texas department of state health services, there are approximately 17.7 million adults (age 18+) living in texas, of which 1.45 million have diabetes. in 2010, 366,921 adult texans were diagnosed with diabetes for the first time.

what is the incidence of diabetes in texas? express your answer in units of per 1000 persons per year

20.73 ≈ 21 persons per year

Step-by-step explanation:

Data provided in the question:

Total population of Texas = 17.7 million

People having diabetes = 1.45 million

Number of new cases of diabetes diagnosed for the first time = 366,921

Now,

the incidence of diabetes in Texas

= [ Number of new cases diagnosed ] ÷ [ Total population ]

= 366,921 ÷ 17.7 million

= 366,921 ÷ 17,700,000

= 0.02073

thus,

the incidence of diabetes in Texas per 1000 persons

=  0.02073 × 1,000

= 20.73 ≈ 21 persons per year

i think this could be a possible answer (1 / 84) -1

good luck! : d

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)