Lisa invests $4,000 in two types of bonds, bond a and bond b. bond a offers a 10% return, and bond b offers a 6% return. lisa invests $x in bond a and $y in bond b. her total return on the investment is $340. the system of linear equations defining the situation is x+y=4,000 and .1x=.06y=340. the amount lisa invested at the rate of 10% is , and the amount she invested at the rate of 6% is .

Lisa invests $4,000 in two types of bonds, bond A and bond B. A + B = 4000 Bond A offers a 10% return, and bond B offers a 6% return. .10 A + .06 B = 340 Her total return on the investment is $340. since the relationship A+B=4000 must satisfy the setup for all values A and B we can state that A = 2000 + n, and B = 2000 -n afterall: 2000 +n + 2000 - n = 4000 for all n .10(2000+n) + .06(2000-n) = 340, once we know n we know A and B

The answer is a because i went through all the other ones that it didn’t come out right

20y5 times 2 is 1010 times -2 is -20, plus y