In a certain study, women's heights are found to be approximately normally distributed with a mean of 61 inches and a standard deviation of 2.5 inches.

a. what would be the z-score for a woman who is 5 feet 3 inches tall?

b. what percentage of women is she taller than?

a. Z=0.8

b. 78.81%

Step-by-step explanation:

The z-score for a woman measuring 'X' inches is given by:

Where μ is the distribution mean and σ is the standard deviation.

Since each feet equals 12 inches, the woman's height is:

a. The z-score is:

b. The percentage of women she is taller than can be found by checking for the corresponding percentile in a z-score table. A z-score of 0.8 is equivalent to the 78.81-th percentile. Therefore, she is taller than 78.81% of women.

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

mx+89b(-98)nb

step-by-step explanation: