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Mathematics, 27.11.2019 00:31 gabbygunshows4530

Jerry solved this equation: 3 ( x βˆ’ 1 4 ) = 13 6
1. 3x βˆ’ 3 4 = 13 6
2. 3x βˆ’ 3 4 + 3 4 = 13 6 + 3 4
3. 3x = 26 12 + 9 12
4. 3x = 35 12
5. ( 3 1 ) 3 1 x = 35 12 ( 3 1 )
6. x = 105 12
in which step did jerry make an error?
a) in step 2, he should have subtracted 3/4 from both sides.
b) in step 3, he should have found an lcd of 10.
c) in step 4, he should have subtracted 9 from 26.
d) in step 5, he should have multiplied both sides by 1.3

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Jerry solved this equation: 3 ( x βˆ’ 1 4 ) = 13 6
1. 3x βˆ’ 3 4 = 13 6
2. 3x βˆ’ 3 4 + 3 4 =...
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