How much water should be added to 6 gallons of pure acid in order to obtain the 24% acid solution?

19 gallons

Step-by-step explanation:

Let x gallons be the amount of water which should be added to 6 gallons of pure acid in order to obtain the 24% acid solution.

Amount of water = x gallons

Amount of pure acid = 6 gallons

Amount of acid solution = x + 6 gallons

Amount of acid in acid solution = 24%

So, there are gallons of acid in acid solution.

Hence,

Solve this equation. Multiply it by 100:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

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