Arectangle has a primeter of 200 ft the length is 4 more feet than the width find the dimensions of the rectangle

The length and width of the given rectangle are 52 ft and 48 ft respectively.

The relationship between the length and breadth is given as following:

The length is 4 more feet than the width

The perimeter of the rectangle is given as 200 ft.

The formula to find the perimeter of a rectangle is:

Perimeter = 2(length + width)

Let length and width of the rectangle be denoted as ‘L’ and ‘B’

The given relationship between length and width can be written in equation form as follows:

L = 4 + B eqn 1

Substitute the value of "L" in perimeter of triangle

200 = 2(4 + B + B)

200 = 2(4 + 2B)

200 = 8 + 4B

4B = 192

B = 48

Since, we know the value of width lets substitute it in eq1 to find the length.

L = 4 + 48

L = 52

Therefore, the length and width of the given rectangle are 52 ft and 48 ft respectively.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0