What is the equation in point slope form of the line that passes through the point
(2, 6) and has a slope of 5?

a) y+2=5(x+6)

b)y-6=5(x+-2)

c)y−2=5(x−6)

dy+6=5(x+2)

B, y-6=5(x-2)

Step-by-step explanation: Point-slope form is y-y1=m(x-x1). Given that in ordered pairs the x point comes first, we know the left part of the equation needs to be y-6. We also know the slope is 5, so the first part of the right side is 5(x-x1). We know that the x is 2, so we have y-6=5(x-2).

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !