Given f(x)=2x^3+x^2-7x-6. find all real and imaginary zeroes. show your work.

The real zeroes of given function is

Given that,

We have to find the real and imaginary zeroes

This can be found out by equating the function to zero and finding the roots "x"

Now, let us use trail and error method.

So put x = 1 in f(x)

f(1) = 2 + 1 – 7 – 6 = - 10  

1 is not a root.  Since f(1) is not equal to 0

Now put x = -1

f(-1) = -2 + 1 + 7 – 6 = 0  

-1 is a root.  Since f(-1) is equal to 0

So, one of the roots is -1. Let the other roots be a, b.

Now, we know that, algebraic identity,

Add (1) and (3)

Hence, the roots of the given equation are

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

answer: 414,377,008

step-by-step explanation:

just multiply it