Lorraine computed a confidence interval for μ based on a sample of size 41. since she did not know σ, she used s in her calculations. lorraine used the normal distribution for the confidence interval instead of a student's t distribution. will her interval be longer or shorter than one obtained by using an appropriate student's t distribution? explain.
shorter. for d. f. = 40, zc is greater than tc. shorter. for d. f. = 40, zc is less than tc. longer. for d. f. = 40, zc is less than tc. longer. for d. f. = 40, zc is greater than tc.

nada

step-by-step explanation:

ok so the answer to your question is simple as long as you look at the different dimensions that contain the exemplary letters that combined in the right order give you words that eventually within the 5th dimension will conform and give you the correct answer to your question. hope i , stop looking at this easily, look at it with a spectral view.

step-by-step explanation:

told you

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.