If g(n) varies inversely with n and g(n) = 8 when n = 3, find the value of n when g(n) = 6.

4

Step-by-step explanation:

g(n) varies inversely with n.

This can be expressed alternatively as \[g(n) = \frac{k}{n}\] where k is a constant value.

Given that when n = 3, g(n) = 8.

This implies, \[8 = \frac{k}{3}\]

Simplifying the equation to solve for k, k = 8 * 3 = 24

Now when g(n) = 6, \[g(n) = \frac{k}{n}\]

\[6 = \frac{24}{n}\]

Calculating the value of n, \[n = \frac{24}{6}\] = 4

So the required value of n is 4.

n = 4 when g(n) = 6

Step-by-step explanation:

If g(n) varies inversely with n

g(n) α 1/n

g(n) = k/n where k is the constant of proportionality

if g(n) = 8 when n = 3, then

8 = k/3

k = 24

g(n) = 24/n

when g(n) = 6

6 = 24/n

6n = 24

n = 24/6

n = 4

this is not the answer this is just a question. is this middle school math?

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    -7                           -7

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