Suppose you have a sample of size 42 with a mean of 30 and a population standard deviation of 7.4. what is the maximal margin of error associated with a 95% confidence interval for the true population mean? as in the reading, in your calculations, use z = 2. give your answer as a decimal, to two places

The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.

Step-by-step explanation:

We have given,

The sample size n=42

The sample mean

The population standard deviation

Let be the level of significance = 0.05

Using the z-distribution table,

The critical value at 5% level of significance and two tailed z-distribution is

The value of margin of error is

The maximal margin of error associated with a 95% confidence interval for the true population mean is 2.238.

its line 2 i just added the rest or else it wouldn't let me answer

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)