There are 39 students in a psychology class. the class has been divided into 10 groups; 9 groups have 4 students in them, 1 group only has 3 students. the instructor puts all of the students names in a hat and then randomly draws 1 name. what are the chances that the one name will be the name of someone in the small, 3-person group?

Our required probability is 0.1875.

Step-by-step explanation:

Since we have given that

Number of students = 39

Total Number of groups = 10

Number of groups containing 4 students = 9

Number of groups containing 3 students = 1

So, Probability of getting group of 4 students =

Probability of getting group of 3 students =

Using the "Bayes theorem":

Probability that the one name will be the name of someone in the small 3-person group is given by

Hence, our required probability is 0.1875.

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

are ya tryin to ask something or is this a statement