Y=2/3(x-5)^2
y=1/2(x-5)^2
y=3/4(x-5)^2
y=-4(x-5)^2
for the quadratic equations, show there which statement is true?
a.) the graph open upward
b.) the graph open downward
c.) the graph is symmetric about the y-axis
d.) the graphs are symmetric about the line x=5

it needs to be turned in today

  see below

Step-by-step explanation:

The graph opens upward if the sign of the squared term is positive. If that sign is negative, the graph opens downward. The first three equations open upward; the last opens downward.

The line of symmetry is the value of x that makes the squared term zero. Here, that is x=5 for all equations.

y=2/3(x-5)^2:  A, D

y=1/2(x-5)^2:  A, D

y=3/4(x-5)^2:  A, D

y=-4(x-5)^2:  B, D

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3