Atheatre has the capacity to seat people across two levels, the circle and
the stalls.
the ratio of the number of seats in the circle to the number of seats in
the stalls is 2: 5
last friday, the audience occupied all the 528 seats in the circle and
the seats in the stalls.
work out the percentage of occupancy of the theatre last friday.

Step-by-step explanation:

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is .

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

Solving for "s", we get:

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

 We know that of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

Therefore, the total number of seats that were occupied las Friday is:

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

Solving for "p", we get:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

21/58.

hope to be marked brainliest