Mathematics, 23.11.2019 09:31 jay7176

Questions:

which display is more useful for approximating the minimum distance?

which display can be used to find that there were 23 vehicles at nam’s used car lot?

Questions: which display is more useful for approximating the minimum distance?

Answers: 2

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Answers

Answer from: djgunderson

See explanation

Step-by-step explanation:

Which display is more useful for approximating the minimum distance?

More useful is box-and-whisker plot (second display) because there you can exactly see that the minimum distance is 10 km (left point at the plot).

Which display can be used to find that there were 23 vehicles at Nam’s Used Car Lot?

More useful is first display, because you see the following information:

Distance Number of vehicles

0 - 50 3

50 - 100 4

100 - 150 5

150 - 200 6

200 - 250 3

250 - 300 2

Total number of vehicles = 3 + 4 + 5 + 6 + 3 + 2 = 23

Answer from: Quest

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

Answer from: Quest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

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