An article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 163 of these passed the probe. assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe. (round your answers to three decimal places.)

(0.4062, 0.5098)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval , we have the following confidence interval of proportions.

In which

Z is the zscore that has a pvalue of

For this problem, we have that:

356 dies were examined by an inspection probe and 163 of these passed the probe. This means that and

Assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe.

So = 0.05, z is the value of Z that has a pvalue of .

The lower limit of this interval is:

The upper limit of this interval is:

The correct answer is

(0.4062, 0.5098)

the answer is 0.071

good luck! : d

c

step-by-step explanation: easy math