From a club 25 people in how many ways can a group of five members be selected to attend conference? a group of 5 members can be selected to a conference in how many ways

²⁵C₅ = 53130

Step-by-step explanation:

number of people in the club = 25

number of people to be selected in the group to attend conference = 5

number of ways of selecting this group from 25 people is same as selecting 5 objects from 25 distinct objects = ²⁵C₅ (Selection)

=

=

= 21×22×23×5

= 53130

∴ Number of ways of selecting this group from 25 people = 53130

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

where is the picture

step-by-step explanation: