Rizio co. purchases a machine for $12,400, terms 2/10, n/60, fob shipping point. the seller prepaid the $280 freight charges, adding the amount to the invoice and bringing its total to $12,680. the machine requires special steel mounting and power connections costing $857. another $404 is paid to assemble the machine and get it into operation. in moving the machine to its steel mounting, $190 in damages occurred. materials costing $40 are used in adjusting the machine to produce a satisfactory product. the adjustments are normal for this machine and are not the result of the damages.
complete the below table to calculate the cost recorded for this machine. (rizio pays for this machine within the cash discount period.)
amount included in cost of equipment: invoice price of machinenet purchase pricetotal cost to be recorded

$13370

Step-by-step explanation:

Please see attachment.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.