Your family goes out to chili's for dinner. chili's charges $9 for an adult dinner and $5 for a
child's plate. ten members of your family went to dinner and your bill was $66. how many
adults and children ate at chili's?

The number of adult's for the dinner is 4  and

The number of child's for the dinner is 6   .

Step-by-step explanation:

Given as :

The total number of members goes for dinner = 10

The total bill for the dinner = $ 66

Let The number of children goes for dinner = C

And the number of adults goes for the dinner = A

The charges for the adults dinner = $ 9 per plate

The charges for the child dinner = $ 5 per plate

So, According to question

 A + C = 10  ......1

9 A + 5 C  = 66         ....2

Solving eq 1 and 2

So,  9 × ( A + C ) =  9 × 10

Or, 9 A + 9 C = 90

    9 A + 5 C = 66

or, ( 9 A + 9 C ) - ( 9 A + 5 C ) = 90 - 66

Or, ( 9 A - 9 A ) + ( 9 C - 5 C ) = 24

or , 0 + 4 C = 24

∴  C =

I.e C = 6

Put The value of C in eq 2

so, 9 A + 5 C  = 66  

or, 9 A + 5 × 6  = 66  

or, 9 A + 30  = 66  

Or, 9 A = 66 - 30

Or, 9 A = 36

∴  A =

i.e A = 4

Hence The number of adult's for the dinner is 4  and The number of child's for the dinner is 6   .  answer

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