Which quadratic equation has roots - 1 + 4i and - 1 - 4i? . (1 point)
a. x^2+2x+2=0
b. 2x^2+x+17=0
c. x^2+x+2=0
d. 2x^2+x+2=0

Question:

Which quadratic equation has the roots -1+4i and -1-4i

A. X^2+2x+2=0

B. 2x^2+x+17=0

C. X^2+2x+17=0

D. 2x^2+x+2=0

Option C

The quadratic equation that has roots -1 + 4i and -1 - 4i is

Solution:

Given, roots of a quadratic equation are (- 1 + 4i) and (- 1 – 4i)

We have to find the quadratic equation with above roots.

Now, as (-1 + 4i) and (-1 – 4i) are roots, x – (-1 + 4i) and x – (-1 – 4i) are factors of quadratic equation.

Then, equation will be product of its factors.

On multiplying each term with the terms in brackets we get,

4ix and -4ix will cancel out each other.

Similarly 4i and -4i will cancel out each other

We know that

Hence we get,

Thus is the required quadratic equation

i dont know sorry

step-by-step explanation:

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^