The width of a rectangle is half as long as the
length. the rectangle has an area of 128 square
feet. what are the length and width of the
rectangle?
separate the answers with a comma.

The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.

Step-by-step explanation:

1. Let's check the information given to resolve the question:

Length of the rectangle = x

Width of the rectangle = x/2 ( half as long as the  length)

Area of the rectangle = 128 square feet

2. Let's find the value of the length and the width

Area of the rectangle = Length of the rectangle * Width of the rectangle

128 = x * x/2

128 = x² /2 (x * x = x²)

256 = x² (Multiplying by 2 to both sides of the equation)

x² = 256

√x² = √ 256

x = 16

The length of the rectangle is 16 feet.

Width of the rectangle = x/2 = 16/2 = 8 feet.

The length of the rectangle is 16 feet, the width of the rectangle is 8 feet.

The rectangle has length = 16 feet, width = 8 feet

Explanation:

Let the length be x, we are given that width is half as long as the length so we can say that width is equal to x/2

We are given the area to be = 128 square feet ,

and we know area = length x breadth

So area =

=>

=> 256 =  

=> x = 16 = length

and width =

which are the required length and breadth of the rectangle

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.