the playing field for a particular sport is a rectangle whose length is 2 more than twice the width. the perimeter of the playing field is 274 feet. find the dimensions of the playing field.
what is the width?
what is the length?

2+x square =274

Step-by-step explanation:

you plug in the numbers you have and make the equation and solve for x

note:

when ever you get x square =# this is you width.

to get the length you square root the number after subtracting 2 from both sides to get the length because it says twice.

I HOPE THAT WILL HELP YOU

Let length = L and width = W

Based from the question, we have:

L = 2W + 2

2(L + W) = 274

Substitute L from first equation to second equation

2((2W + 2) + W) = 274

W = 45 feet

L = 2W + 2 = 2(45) + 2 = 92 feet

so, converting firstly the mixed fractions to improper fractions and then "adding".