Use the mean value theorem to determine the area of f(x)= 2x^2+3 on the interval [0 , 2]

The area of given function is 5.67  unit²

Step-by-step explanation:

Given function f(x) as :

f(x) = 2 x² + 3

The interval in which f(x) lies [ 0 , 2 ]

Let The area for the curve = A

Or ,  A =

Or, A =

Or, A =

or, A =

or, A = ( + 6 )

Or, A =   ×

∴ A = 5.67  unit²

Hence The area of given function is 5.67  unit²   Answer

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