Abag of m& ms was randomly selected from the grocery store shelf, and the color counts were: brown 24 red 22 yellow 20 orange 15 green 15 blue 15 .find the 95% confidence interval for the proportion of red m& ms in that bag.

(0.1239,0.2721)

Step-by-step explanation:

Given : A bag of M&Ms was randomly selected from the grocery store shelf, and the color counts were:

Brown 24 Red 22 Yellow 20 Orange 15 Green 15 Blue 15

Total M&Ms = 24+22+20+15+15+15=111

The confidence interval for population proportion is given by :-

, = sample proportion.

where n= sample size.

= Two -tailed z-value for confidence level of c.

Let p be the population proportion of red M&Ms in that bag.

As per given , we have

n= 111

Two -tailed z-value for 95% confidence level

Then, the  95% confidence interval for the proportion of red M&Ms in that bag will be :-

Hence, the 95% confidence interval for the proportion of red M&Ms in that bag=(0.1239,0.2721)

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: