In this problem, we will explore the intersection of bayesian and frequentist inference. let , , ⋯ , ∼i. i.d ,theta) , for some unknown positive number theta , which is our parameter of interest. suppose that we are unable to come up with a prior distribution for theta . (a) 1 point possible (graded) compute the maximum likelihood estimator of theta . you may use the variables , ∑= , and ∑= . (enter sigma x_i(x_i) for ∑= and sigma _i(x_i^2) for ∑= . do not worry if the parser does not render properly; the grader works independently. if you wish to have proper rendering, enclose sigma_i(x_i) by brackets. )

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

it's d

step-by-step explanation:

we need to see the graph to know but

strong positive is if it is going up from left to right in a straight diagonal line (like this /)

strong negative is the same but from right to left (like this \)

weak negative is the same as strong negative but its more straight line still right to left

and weak positive is the same as strong positive but more a straight line still left to right though.