Given the force field f, find the work required to move an object on the given oriented curve.
f = on the path consisting of the line segment from (-1,0) to (0,8) followed by the line segment from (0,8) to (2,8)

67/4

Step-by-step explanation:

Let C, D be the line segments that join (-1,0) with (0,8) and (0,8) with (2,8) respectively.

The work required by the force field F(x,y)=(x,y) is the curve integral

the line segments that joins (-1,0) with (0,8) can be parameterized as

r(t) = t(0,8)+(1-t)(-1,0)=(t-1,8t) with 0≤ t≤ 1

So

the line segments that joins (0,8) with (2,8) can be parameterized as

r(t) = t(2,8)+(1-t)(0,8)=(2t,8) with 0≤ t≤ 1

hence

and we have the work required by F to move a particle alon the path is

answer: 2 and 1

step-by-step explanation: got this question

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!