Suppose a network has 40 computers of which 5 fail. (a) how many possibilities are there for the five that fail? (b) suppose that 3 of the computers in the network have a copy of a particular file. how many sets of failures wipe out all the copies of the file? that is, how many 5-subsets contain the three computers that have the file?

a) 658008, b) 666.

Step-by-step explanation:

Since we have given that

Total number of computers = 40

Number of failed computers = 5

(a) How many possibilities are there for the five that fail?

We will use "Combination" to find all 5 failed.

(b) Suppose that 3 of the computers in the network have a copy of a particular file. How many sets of failures wipe out all the copies of the file?

So, number of computers failed left = 5-3 =2

Total number of computers = 40-3=37

So, the number of set of failures wipe out would be

Hence, a) 658008, b) 666.

i believe the answer is c.

constant of proportionality = 3 and the equation is c = 3p.

step-by-step explanation:

c = kp   where c = amount of caffeine in mg., p = oz of pepsi and k is the constant of proportionality.

substituting the values given:

24 = 8k

k = 3.

the same value of k will be obtained if we substitute the other given values.