The equation of motion of a block with mass m = 8 kg. attached to a spring whose spring constant is k = 2 and which starts from rest at a point 3 cm above equilibrium is 8x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0.a. true. b. false.

FALSE

Step-by-step explanation:

In order to be consistent with the system of unit we should decide if we are going to work with the CGS system (centimeter-gram-second) or the MKS system (meter-kilogram-second).

If we decide to work with the CGS system, the equation of motion would be

8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0

since 1 Kg = 1,000 g

If we decide to work with the MKS system, the equation of motion would be

8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0

given that 1 mt = 100 cm

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3

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step-by-step explanation: