What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?

y = –one-fourthx + 33
y = –one-fourthx + 36
y = 4x − 16
y = 4x + 16

Option D

The equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32) is y = 4x + 16

Solution:

Given that the line passes through point (4, 32)

The line is parallel to y − 1 = 4(x + 3) ---- eqn 1

First let us find the slope of line

The general form of point slope form of line is given as:

 ----- eqn 2

Where "m" is the slope of line

Comparing the eqn 2 with eqn1  y − 1 = 4(x + 3)

We get "m" = 4

The slopes of parallel lines are always equal

Hence the slope of line passing through (4, 32) has the same slope "m" = 4

Now plug in "m" = 4 and in eqn 2 to get the required equation of line

y - 32 = 4(x - 4)

y - 32 = 4x - 16

y = 4x - 16 + 32

y = 4x + 16

Thus the equation of line parallel to given line is y = 4x + 16

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation: