Let point l be between m and n on mn. given that mn=31, ml= h-15 and ln = 2h-8. find ln

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

 h = 18

substituting the value of h to the expression for LN obtaining

LN = 2h – 8

LN = 2(18) – 8

LN = 28

Therefore the length of the segment LN is 28 units

the answer is c

step-by-step explanation:

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