The price of stock a. m. 9 am was $12.73 cents and the price has been increasing at the rate of six cents per hour at noon the price of stock to you is $13.48 ginza decrease at the rate of $.14 per hour if the stocks continue to increase and decrease at the same rate in how many hours are the prices of stock to be the same

Since, the price of stock A initially at 9 am was $16.15

After every hour, the price has been increasing at the rate of $0.06.

Let t be initial time (i.e, 9am) in hours.

Then, the price of stock A represents in the form of equation is;

16.15+0.06t

And, the price for stock B at noon was $ 16.90.

If it decreases at the rate of $0.12 each hour.

Then, the price of stock represents in the form of equation is:

16.90 - 0.12(t-3)  

If the prices of stock A and Stock B will be same then;

16.15+0.06t =16.90 - 0.12(t-3)  

Using distributive property on RHS, ( )

16.15 +0.06t = 16.90 - 0.12t + 0.36

Simplify:

Combine like terms;

0.18t = 0.75+0.36

or

0.18t =1.11

Divide 0.18 both sides we get;

t = 6.16666667≈6.17 hour

The price of two stocks will be same after t≈6.17 hours at 3:10 PM

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