For what values of k does (k+1)x2−6x+5=0 have two equal real roots?

k =

Step-by-step explanation:

Using the determinant Δ = b² - 4ac to determine the value of k

The condition for the equation to have 2 equal real roots is

b² - 4ac = 0

Given

(k + 1)x² - 6x + 5 = 0 ← in standard form

with a = k + 1, b = - 6 and c = 5, then

(- 6)² - 4(k + 1) × 5 = 0, that is

36 - 20(k + 1) = 0 ← distribute and simplify left side

36 - 20k - 20 = 0

16 - 20k = 0 ( subtract 16 from both sides )

- 20k = - 16 ( divide both sides by - 20 )

k = =

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt

6 meters

step-by-step explanation: