Line segment w y is an altitude in triangle wxz.

triangle w x z is shown. an altitude is drawn from point w to point y on side z x, forming a right angle. angles z w y and w x y are congruent.

if δywz ~ δyxw, what is true about anglexwz?

anglexwz is an obtuse angle.

anglexwz is a right angle.

anglexwz is congruent to anglewxy.

anglexwz is congruent to anglexzw.

The angle XWZ is right angle.

Step-by-step explanation:

See the given diagram.

In triangle WXZ, WY is an altitude.

So, ∠ WYZ = ∠ XYW = 90°

Now, given that ∠ ZWY = ∠ WXY.

Now, from Δ XYW, since, ∠ XYW = 90° so, ∠ WXY + ∠ YWX = 90° (1)

⇒  ∠ ZWY + ∠ YWX =  90° {Since, ∠ ZWY = ∠ WXY}

⇒ ∠ XWZ = 90°

Therefore, the angle XWZ is right angle. (Answer)

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!