Suppose that p(n) is a propositional function. determinefor which nonnegative integers n the statement p(n) must be ) p(0) is true; for all nonnegative integers n, if p(n) istrue, then p(n+2) is true. b)p(0) is true, for all nonnegative integers n, if p(n) istrue, then p(n+3) is true. c)p(0) and p(1) are true; for all nonnegative integers n , ifp(n) and p(n+1) are true, then p(n+2) is true. d)p(0) is true; for all nonnegative integers n, if p(n) istrue, then p(n+2) and p(n+3) are true.

congruent segments

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

8

step-by-step explanation:

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.