Suppose 250 randomly selected people are surveyed to determine if they own a tablet. of the 250 surveyed, 98 reported owning a tablet. using a 95% confidence level, compute a confidence interval estimate for the true proportion of people who own tablets.

The true proportion for the population would be between 0.386 and 0,398 (0.392±0.06) in 95% confidence level.

Step-by-step explanation:

Confidence interval for true population proportion can be computed as p±ME where

and margin of error (ME) can be found using the formula

ME= where

Using the numbers

ME= ≈ 0.06

Then the true proportion for the population would be p±ME = 0.392±0.06 in 95% confidence level.

hello,

b) 62.47% of the students are between 14 and 18 years old.

step-by-step explanation:

mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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step-by-step explanation: