On the moon, the acceleration due to gravity is -1.6 meters per second per second. a stone is dropped from a cliff on the moon and hits the surface of the moon 20 seconds later. a) how far did it fall? b) what was its velocity at impact?

How far did it fall? -320 meters

What was its velocity at impact? -32 m/s

Step-by-step explanation:

a) How far did it fall?

To calculate the distance traveled by the stone we must use the following formula:

Sustituing the given values we have that:

The distance traveled by the stone was -320 meters under the released point

b) What was its velocity at impact?

To calculate the velocity we need to use the formula:

Sustituing the given values we have that:

So the velocity is -32 meteres per second, the negative sign indicate that the object is going down

geometry: triangles

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answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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