The given  system as (3,3) as its solution.
Step-by-step explanation:
Here, the given system of the equation is:
4 x + 2 y = 18
 (1)
2 x + 3 y = 15 Â Â Â Â (2)
Now, to use the elimination method, w need to eliminate any of the variable.
Eliminate the variable x in the given system.
Multiply equation (2) with -2 Â we get,
(2 x + 3 y = 15  )(-2) ⇒ -4x - 6y = -30   (3)
Add (1) and (3), we get:
4 x + 2 y  -4x - 6y   = 18  -30
or, - 4 y = - 12
or, y =  12/4 = 3   ⇒ y = 3
Putting in (1), we get
4x + 2(3)  = 18  or, 4x   = 18 - 6 = 12
or, x  = 3
(x,y) Â = (3,3)
Hence, the above system as (3,3) as its solution.