Aplayer rolls a die and receives the number of dollars equal to the number on the die except when the die shows a 6. if a 6 is rolled, the player loses $6. if the game is to be fair, what should be the cost to play?

We expect to win k dollars with probability 1/6 if k is between 1 and 5, and we lose 6 dollars with probability 1/6. So, the expected value for this random variable is

So, you win on average 1.5 dollars, and if that's the cost to play, the game is fair.

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7