My question is 2x^2+13x+6=0 there are no numbers that multiply to 6 and can add to 13. i'm so !

Look

2x^2+13x+6
factored into
(ax+b)(cx+d)
we need to find a,b,c,d such that when multipied we get 2x^2+13x+6
first
we know that the first number hast to be 2
(2x+somethin)(1x+sometin)
and the end numbers have to multiply to 6
if we try 1 and 6
(2x+1)(x+6)=
2x^2+x+12x+6=
2x^2+13x+6
correct

so
2x^2+13x+6=0=(2x+1)(x+6)

therefor assume
2x+1=0 and x+6=0

2x+1=0
minus 1
2x=-1
divide 2
x=-1/2

other one
x+6=0
mnus 6
x=-6

x=-6 or -1/2

Answerthe simplified expression isexplanationthe given expression is,let us deal with the bracket first.the two negatives in the parenthesis will become positive.the expression now becomes,we now expand the parenthesis to get,we group like terms to obtain,this simplifies to,