Variable gender n mean stdev minimum maximum
exercise f 30 9.40 741 0.00 34.00
m 2 0 12....
Mathematics, 17.11.2019 23:31 muhammadcorley123456
Variable gender n mean stdev minimum maximum
exercise f 30 9.40 741 0.00 34.00
m 2 0 12.40 8.80 2.00 30.00
discuss whether or not the methods described below
would be appropriate ways to generate randomiza-
tion samples that are consistent with h, he = hm
vs h, hf # hm explain your reasoning in each
case.
(a) randomly label 30 of the actual exercise values
with "f" for the female group and the remaining
20 exercise values with "m" for the males. com-
pute the difference in the sample means, ip-xm-
(b) add 1.2 to every female exercise value to give
a new mean of 10.6 and subtract 1.8 from each
male exercise value to move their mean to 10.6
(and match the females). sample 30 values (with
replacement) from the shifted female values and
20 values (with replacement) from the shifted
male values. compute the difference in the sam
ple means, xp - xm.
(c) combine all 50 sample values into one set of data
having a mean amount of 10.6 hours. select 30
values (with replacement) to represent a sam-
ple of female exercise hours and 20 values (also
with replacement) for a sample of male exercise
values. compute the difference in the sample
means, xp - im
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