Me w a geometry question i need it super soon pl

answer:

nice status update, you would save time.by just posting it in the frist place instead have people search for it.

answer: choice 3

translate triangle abc so that point b lies on point d to confirm that angle b is congruent to angle d

step-by-step explanation:

explanation:

the triangles are congruent by the aa (angle angle) similarity theorem only if we can find a pair of angles that match up and are congruent. we're already given that "angle a is congruent to itself" (more technically: angle bac = angle dae). so this is the first pair of angles we need.

the second pair of angles could be sliding the triangle up so that point b overlaps point d; also the angles match up as well to confirm they are the same measure. if we can do this, then we have shown that angle b is congruent to angle d. an alternative is to slide triangle abc to the right so that angle c lines up with angle e. though this answer choice is not listed.

side note: choice 2 and choice 4 would only apply if you are trying to prove similarity through the sas similarity theorem.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!